8q+18=(4q^2+18q+81)/q

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Solution for 8q+18=(4q^2+18q+81)/q equation: 


D( q )

q = 0

q = 0

q = 0

q in (-oo:0) U (0:+oo)

8*q+18 = (4*q^2+18*q+81)/q // - (4*q^2+18*q+81)/q

8*q-((4*q^2+18*q+81)/q)+18 = 0

(-1*(4*q^2+18*q+81))/q+8*q+18 = 0

(-1*(4*q^2+18*q+81))/q+(8*q*q)/q+(18*q)/q = 0

8*q*q-1*(4*q^2+18*q+81)+18*q = 0

4*q^2-18*q+18*q-81 = 0

4*q^2-81 = 0

(4*q^2-81)/q = 0

(4*q^2-81)/q = 0 // * q

4*q^2-81 = 0

4*q^2 = 81 // : 4

q^2 = 81/4

q^2 = 81/4 // ^ 1/2

abs(q) = 9/2

q = 9/2 or q = -9/2

q in { 9/2, -9/2 }

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